Acids and bases · Lesson 2
A scale made of powers of ten
Pure water is never just H₂O. A tiny fraction of its molecules are always swapping protons, and that fixes the link between hydrogen ion and hydroxide in every solution. The pH scale turns those tiny numbers into ones you can use.
In 1909 the Danish chemist Søren Sørensen was working at the Carlsberg Laboratory in Copenhagen, the research institute founded by the brewery. He was studying how enzymes and proteins behave, and he kept running into the same problem: the concentration of hydrogen ions in his solutions could be 0.1 mol per litre in one flask and 0.000 000 1 in the next. Writing numbers like that all day is miserable, and comparing them is worse.
His solution was to use the power of ten instead of the number itself. A hydrogen ion concentration of 10−3 became simply “3”. He called it pH. (The p is usually said to stand for power, although historians still argue about it.)
More than a century later, pH is on shampoo bottles and swimming-pool test kits, and in every Year 12 chemistry exam. Behind it sits a simple equilibrium that is happening inside every glass of water you have ever drunk.
Water ionises itself
A tiny fraction of water molecules ionise into hydrogen ions and hydroxide ions:
H2O(l) ⇌ H+(aq) + OH−(aq)
This self-ionisation happens to only about two molecules in every billion at 25 °C, and the ions recombine almost as soon as they meet. It is a dynamic equilibrium, and its equilibrium constant is the ionisation constant of water:
\[K_\mathrm{w} = [\mathrm{H^{+}}][\mathrm{OH^{-}}] = 1.0 \times 10^{-14} \quad \text{at 25 °C}\]Liquid water is left out of the expression as usual. In pure water the ions are formed in pairs, so [H+] = [OH−] = 1.0 × 10−7 mol L−1.
Water, up close
Kw holds in every aqueous solution
Add acid to water and [H+] rises. The reverse reaction (H+ meeting OH−) speeds up, so hydroxide ions are used up until the product [H+][OH−] is back to 1.0 × 10−14. So at 25 °C, in any aqueous solution:
- an acidic solution has [H+] greater than [OH−];
- a neutral solution has them equal;
- a basic solution has [OH−] greater than [H+];
- you can always find one from the other: \([\mathrm{OH^{-}}] = \dfrac{K_\mathrm{w}}{[\mathrm{H^{+}}]}\).
For example, if [H+] = 2.0 × 10−3 mol L−1, then [OH−] = 1.0 × 10−14 ÷ 2.0 × 10−3 = 5.0 × 10−12 mol L−1. Even a strongly acidic solution contains some hydroxide ions.
The pH scale
\[\mathrm{pH} = -\log_{10}[\mathrm{H^{+}}] \qquad [\mathrm{H^{+}}] = 10^{-\mathrm{pH}}\]At 25 °C, pH 7 is neutral, below 7 is acidic and above 7 is basic. Because pH is a logarithm, each step of one unit is a factor of 10 in [H+]: a solution of pH 2 has 1000 times the hydrogen ion concentration of a solution of pH 5. pH can be negative or greater than 14 for very concentrated solutions.
Significant figures in pH
The number of decimal places in a pH equals the number of significant figures in the concentration. [H+] = 3.2 × 10−4 mol L−1 (2 significant figures) gives pH = 3.49 (2 decimal places).
Calculating pH
Strong acids. A monoprotic strong acid is fully ionised, so [H+] equals the acid concentration. For 0.025 mol L−1 HCl, \(\mathrm{pH} = -\log(0.025) = 1.60\).
Strong bases. Find [OH−] first (remember that Ba(OH)2 gives two OH− per formula unit), then use Kw. For 0.0050 mol L−1 NaOH, \([\mathrm{H^{+}}] = \dfrac{1.0 \times 10^{-14}}{5.0 \times 10^{-3}} = 2.0 \times 10^{-12}\) mol L−1, so pH = 11.70.
Dilution. The amount of acid is unchanged, so c1V1 = c2V2. Diluting a strong acid tenfold raises its pH by exactly one unit. But dilution can never push an acid past pH 7: once [H+] from the acid becomes tiny, the ions from water itself take over and the pH approaches 7.
Mixing an acid with a base. Work in moles. The H+ and OH− neutralise each other one to one; whichever is in excess sets the pH, after dividing by the total volume.
A pH calculation checklist
- Is the solution acidic or basic? For a base, find [OH−] first.
- For mixtures, calculate moles of H+ and OH−, subtract, and divide the excess by the total volume in litres.
- Convert to [H+] (using Kw if needed), take −log, and round to the right number of decimal places.
- Sense check: an acid must have pH below 7 and a base above 7 (at 25 °C).
Temperature changes Kw
The self-ionisation of water is endothermic (ΔH ≈ +57 kJ mol−1). From Lesson 4 of the equilibrium unit, K for an endothermic reaction increases with temperature, so Kw increases:
| Temperature | Kw | pH of neutral water |
|---|---|---|
| 0 °C | 1.1 × 10−15 | 7.48 |
| 25 °C | 1.0 × 10−14 | 7.00 |
| 37 °C | 2.4 × 10−14 | 6.81 |
| 50 °C | 5.5 × 10−14 | 6.63 |
So pure water at 50 °C has a pH of 6.63, yet it is not acidic. Neutral means [H+] = [OH−], and that is still true: both ions increased equally. pH 7 is the neutral point only at 25 °C.
Common traps
- For a base, −log[OH−] is not the pH. Convert with Kw first.
- Mixing two acid solutions does not average their pH values. Add the moles of H+ and divide by the total volume.
- “pH less than 7 means acidic” is only true at 25 °C.
Higher85 Chemistry
Unlock every question, test and exam
Continue- Worked methods and examples for all 21 lessons
- 630 practice and harder questions with full solutions
- 10 timed topic tests with marking keys
- 10 full Semester 1 and WACE practice exams
Studying Maths Methods too? Get both subjects for $100
Lesson stories, 3D labs and the Chemical equilibrium topic stay free for everyone.