Chemical equilibrium · Lesson 4
The one change that moves K
Heating speeds up every reaction, yet for many equilibria it lowers the yield. Temperature is the only disturbance that changes K itself, and it forces industry into a compromise between rate and yield.
In 1909 Fritz Haber showed that nitrogen from the air could be combined with hydrogen to make ammonia, and within a few years Carl Bosch had scaled the process up to industrial size. Ammonia became fertiliser, and fertiliser fed a world whose population has since quadrupled. It has been estimated that about half of the nitrogen atoms in your body have passed through a Haber–Bosch reactor.
The chemistry is simple: N2(g) + 3H2(g) ⇌ 2NH3(g), ΔH = −92 kJ mol−1. The engineering is a puzzle. The reaction is exothermic, so the cooler the reactor, the more ammonia there is at equilibrium. But nitrogen’s triple bond is very strong, and at low temperatures the reaction is so slow that equilibrium would take years to reach. Heat the reactor and the reaction speeds up, but the yield falls.
Industry settles on a compromise of about 400–450 °C with an iron catalyst. This lesson explains why temperature is the one change that alters the equilibrium constant itself, and why it pulls rate and yield in opposite directions for an exothermic reaction.
Temperature is different
Changing a concentration, a volume or adding a catalyst never changes the value of K. Changing the temperature does. The rule depends on the sign of ΔH:
- If the forward reaction is endothermic (ΔH positive), raising the temperature increases K: the equilibrium shifts to the right.
- If the forward reaction is exothermic (ΔH negative), raising the temperature decreases K: the equilibrium shifts to the left.
Le Chatelier’s principle gives the same prediction if you treat heat as a reactant or product. Adding heat is partially counteracted by the direction that absorbs heat, the endothermic direction. Cooling favours the exothermic direction, which releases heat.
| Equilibrium | ΔH of forward reaction | When heated |
|---|---|---|
| N2O4(g) ⇌ 2NO2(g) | +57 kJ mol−1 | K increases; darker brown |
| Co(H2O)62+(aq) + 4Cl−(aq) ⇌ CoCl42−(aq) + 6H2O(l) | positive | K increases; bluer |
| Fe3+(aq) + SCN−(aq) ⇌ FeSCN2+(aq) | negative | K decreases; paler red |
| N2(g) + 3H2(g) ⇌ 2NH3(g) | −92 kJ mol−1 | K decreases; less ammonia |
Why the endothermic direction wins when you heat
Look at any energy profile. The endothermic direction always has the larger activation energy, by exactly the size of ΔH, because it starts from the lower-energy side of the same peak.
In Lesson 1 you saw that the higher the activation energy, the more sensitive a rate is to temperature. So when an equilibrium mixture is heated, both rates increase, because a greater fraction of collisions have enough energy in both directions. But the endothermic rate increases by a greater factor. For a while the endothermic direction is faster, so there is a net reaction in that direction until the rates are equal again.
Energy landscape
What the graphs look like
A temperature change is the only disturbance in which both rates jump by different factors while no concentration jumps. The concentrations simply start to drift towards their new equilibrium values.
Heating and cooling an equilibrium
Rate versus yield: the industrial compromise
For the Haber process the conditions that give a high yield and those that give a high rate are not the same:
| Condition | Effect on yield | Effect on rate | Industrial choice |
|---|---|---|---|
| Temperature | low temperature favours NH3 (exothermic) | high temperature is faster | about 400–450 °C, a compromise |
| Pressure | high pressure favours NH3 (4 mol gas → 2 mol) | high pressure is faster | about 200 atm, limited by the cost and safety of equipment |
| Catalyst | no effect | much faster | iron catalyst, which makes a lower temperature workable |
| Removing NH3 | increases conversion | – | ammonia is liquefied and removed; unreacted gas is recycled |
The catalyst does not improve the equilibrium yield at all, but it matters enormously: because it makes the reaction fast at a lower temperature, the plant can run cooler than it otherwise could, and a cooler reactor means a higher yield.
Every disturbance in one table
| Change | Rates at that instant | Shift | K |
|---|---|---|---|
| Add a reactant | forward jumps | forward | unchanged |
| Add a product | reverse jumps | reverse | unchanged |
| Decrease the volume (gases) | both jump; the side with more gas particles jumps more | towards fewer gas particles | unchanged |
| Dilute a solution | both fall; the side with more dissolved particles falls more | towards more dissolved particles | unchanged |
| Catalyst | both jump equally | none | unchanged |
| Inert gas at constant volume | no change | none | unchanged |
| Raise the temperature | both jump; the endothermic direction jumps more | endothermic direction | changes |
A full-mark temperature explanation
- Increasing the temperature increases the average kinetic energy, so a greater fraction of collisions have at least Ea: both the forward and reverse rates increase.
- The endothermic direction has the larger activation energy, so its rate increases by a greater factor.
- So there is a net reaction in the endothermic direction until the rates are equal again. State the effect on the amounts (and colour) and on K.
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